Iron(II) perchlorate is the inorganic compound with the formula Fe(ClO 4) 2 ·6H 2 O. A green, water-soluble solid, it is produced by the reaction of iron metal with dilute perchloric acid followed by evaporation of the solution: [3] Fe + 2 HClO 4 + 6 H 2 O → Fe(ClO 4) 2 ·6H 2 O + H 2

May 12, 2021 · To write the formula for Iron (II) perchlorate we’ll use the Periodic Table, a Common Ion Table, and follow some simple rules. Because Iron (II) perchlorate has a polyatomic ion (the...

Jul 12, 2023 · In the names of these oxoanions, the prefix per- is used to identify the oxoanion with the most oxygen (so that ClO 4 − is perchlorate and ClO 3 − is chlorate), and the prefix hypo- is used to identify the anion with the fewest oxygen (ClO 2 − is chlorite and ClO − is hypochlorite).

Ferrous perchlorate Molecular Formula ClHO 4. 1 / 2 Fe Discover more in SciFinder

Iron(II) perchlorate is the inorganic compound with the formula Fe(ClO 4) 2 · 6H 2 O. A green, water-soluble solid, it is produced by the reaction of iron metal with dilute perchloric acid followed by evaporation of the solution: [3] Fe + 2 HClO 4 + 6 H 2 O → Fe(ClO 4) 2 · 6H 2 O + H 2

May 30, 2024 · The formula for ferrous perchlorate is Fe (ClO4)2. Copyright ©2025 Infospace Holdings LLC, A System1 Company. All Rights Reserved. The material on this site can not be reproduced,...

Iron(II) perchlorate hydrate 98%; CAS Number: 335159-18-7; EC Number: 237-704-4; Synonyms: Ferrous perchlorate hydrate; Linear Formula: Fe(ClO4)2 · xH2O at Sigma-Aldrich

ChemSpider record containing structure, synonyms, properties, vendors and database links for iron perchlorate, CKFMJXZQTNRXGX-UHFFFAOYSA-L

Iron(II) Perchlorate Fe(ClO4)2 Molecular Weight, molar mass converter. ... Formula: Fe(ClO 4) 2. Molar Mass: 254.7462 » Fe(ClO4)2 Mass Concentration to Molar Concentration Converter. ... Iron(II) Chlorate • Mg(ClO 4) 2. Magnesium Perchlorate • Ca(ClO 4) …

Sep 18, 2015 · They are asking you to use the elemental symbols from the periodic table to come up with the chemical formula for each compound. This requires a knowledge of polyatomic ions and the electrical charge of each species, I've listed the answers below: