Gilbertsville New York

Gilbertsville is a village in Otsego County, New York, United States. The population was 399 at the 2010 census. The village is in the town of Butternuts and is west of Oneonta. Gilbertsville is located at 42°28′10″N 75°19′16″W / 42.46944°N 75.32111°W.

Elevation: 1,093 ft (333 m)
Country: United States
State: New York
County: Otsego
Town: Butternuts
ZIP code: 13776
Area code: 607

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Gilbertsville New York | The 10 Best Hotels (2025)
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Data from: en.wikipedia.org

Gilbertsville New York

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Gilbertsville New York | The 10 Best Hotels (2025)

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